Question

Prove that :-

$\quad \leadsto \quad \bf \zeta ( z ) = \displaystyle \bf \sum_{\bf n=1}^{\infty} \bf \dfrac{1}{n^x} \cdot e^{-iy \cdot log ( n )}$

Where , z = x + yi

Riemann Hypothesis :) ​

Answer 1

Answer:

theorem

Theorem 1 : If. ∑∞ n=1 an converges then an → 0. Proof : Sn+1 − Sn = an+1 ... the convergence or the divergence of a series by comparing it to one whose

Answer 2

Answer:

(z−4)2/(z−8)2=1

−z+2=−2z+8

−x−yi+2=−2(x+yi)+8

x=6,y=0.