Math, asked by XxCharmingGuyxX, 10 days ago

Prove that :-
___________
(secθ+cosθ)(secθ-cosθ) =  { \tan}^{2}  θ +  { \sin }^{2} θ

Answers

Answered by Anonymous
9

Step-by-step explanation:

(sec©+cos©)(sec©-cos©)

use

(a+b) (a-b) =a²-b²

so we get

(sec²©-cos²©)

(tan²©+1-cos²©)

(tan²©+sin²©)

we know

sin²©+cos²©=1

hope u understand

mark as brilliant

Answered by kritee88
2

Answer:

Hope this will help you.

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