Question

Prove that
$\sf\dfrac{sec8 \theta -1}{sec4\theta-1} = \dfrac{tan8\theta}{tan2\theta}$

Answer 1

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Answer 2

Answer:

$ANSWER:</p><p></p><p>dy/dx = (3x² + y² - 2xy) / (3y² + x² - 2xy).</p><p></p><p>$