Question

Prove that :
$\sin(30) + \tan(45) - \csc(60) \div \sec(30) + \cos(60) + \cot(45) =$

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Answer 1

sin(30) + tan (45) - csc (60) ÷ sec (30) + cos (60) + cot (45) =?

= 1/2 + 1 - 2/root 3 ÷ 2/ root 3 + 1/2 + 1

= 1/2 + 1 - 2/root 3 × root3/2 + 1/2 +1

= 1/2 +1 - 1 + 1/2 + 1

= 1+2/2 - 2+1/2 + 1

= 3/2 - 3/2 +1

= 3-3+2/2

= 2/2

=1

Answer is 1