Question

Prove that ...........



$\sin(90) = 1 \\ \\ class \: = \geqslant 9$
​

Answer 1

$\mathfrak{\huge{\green{Answer}}}$

SINCE,

SIN(2A)=2SIN(A)COS(A)

THEN,

LET US ASSUME 2A=90

->A=45

SUBSTITUTING,

SIN(2*45)=2SIN(45)COS(45)

SIN(90)=2SIN(45)COS(45)

TAKING RHS,

2SIN(45)COS(45)

->2*1/2

->1

HENCE, $<font color="blue">$SIN 90=1

➡️HENCE PROVED.....

$\mathfrak{\huge{\orange{Thanks}}}$

Answer 2

$\huge\bf\pink{{\mid{\overline{\underline{your\: answer}}}\mid}}$

WE KNOW...

$\huge\bf\pink{{\mid{\overline{\underline{</u></strong><strong><u> </u></strong><strong><u>SIN(2A)=2SIN(A)COS(A)</u></strong><strong><u>}}}\mid}}$

SIN(2A)=2SIN(A)COS(A)

THEN,

AFTER ASSUMING,

▶2A=90

WE GET;

▶A=45

SUBSTITUTING,

▶SIN(2*45)=2SIN(45)COS(45)

WE GET RESULT....

▶SIN(90)=2SIN(45)COS(45)

NOW TAKING RHS,

▶2SIN(45)COS(45)

▶2*1/2

▶1

AND LHS,

SIN90°

THEREFORE IT IS PROVED THAT ...

$\huge\bf\pink{{\mid{\overline{\underline{sin 90°=1}}}\mid}}$

THANKS...!!!!!