Question

prove that
$\sin(x + y) \div \sin(x - y) = \tan \: x \ + tan \: y \div \tan \: x \tan \: y$
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Answer 1

Step-by-step explanation:

Please refer to a Proof in the Explanation. Explanation: We have, tanx+tany=sinxcosx+sin ycosy ,. =sinxcosy+cosxsinycosxcosy ,.