Prove that :-
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Step-by-step explanation:
Given :-
Sin 12° Sin 48° Sin 54°
Required To Prove :-
Prove that Sin 12° Sin 48° Sin 54° = 1/8
Solution :-
On taking LHS :
Sin 12° Sin 48° Sin 54°
On multiplying and dividing by 2 then
=> (1/2)[2 Sin 12° Sin 48° Sin 54°]
It can be rearranged as
=> (1/2) [2 Sin 12° Sin 48°] Sin 54°
=> (1/2) [ 2 Sin 48° Sin 12° ] Sin 54°
We know that
Sin A Sin B = (1/2)[Cos (A-B) - Cos(A+B)]
We have , A = 48° and B = 12°
=> (1/2)[2(1/2){Cos(48°-12°)-Cos(48°+12°)}] Sin 54°
=> (1/2)[ (2/2) Cos 36° - Cos 60° ] Sin 54°
=> (1/2) [ (Cos 36° - Cos 60° ] Sin 54°
We know that
Cos 60° = 1/2
=> (1/2) [ Cos 36° - (1/2) ] Sin 54°
=> (1/2) [ (2 Cos 36°-1)/2 ] Sin 54°
=> (1/4) [ 2 Cos 36° -1] Sin 54°
=> (1/4) [ 2 Cos 36° Sin 54° - Sin 54° ]
We know that
Cos A Sin B = (1/2) [ Sin (A+B) - Sin (A-B) ]
We have , A = 36° , B = 54°
=> (1/4) [ 2 (1/2) Sin (36°+54°) -Sin (36-54°) -Sin 54°]
=> (1/4) [(2/2) Sin 90° - Sin (-18° ) - Sin 54°]
We know that
Sin (-A) = -Sin A
=> (1/4) [ Sin 90° + Sin 18° - Sin 54° ]
We know that
Sin 90° = 1
=> (1/4) [ 1 + Sin 18° - Sin 54° ]
We know that
Sin 18° = (√5-1)/4
Sin 54° = (√5+1)/4
On Substituting these values in the above expression
=> (1/4) [ 1+ { (√5-1)/4} - {(√5+1)/4}]
=>(1/4) [ 1+ {(√5-1)-(√5+1)}/4]
=> (1/4) [ 1+ {(√5-1-√5-1)/4} ]
=> (1/4) [ 1+ {(-1-1)/4} ]
=> (1/4) [1+(-2/4) ]
=> (1/4) [ 1+(-1/2) ]
=> (1/4) [ (2-1)/2)]
=> (1/4) (1/2)
=> (1×1)/(2×4)
=> 1/8
=> RHS
=> LHS = RHS
Hence, Proved.
Answer:-
Sin 12° Sin 48° Sin 54° = 1/8
Used formulae:-
→ Sin A Sin B = (1/2)[Cos (A-B) - Cos(A+B)]
→ Cos A Sin B = (1/2) [ Sin (A+B) - Sin (A-B) ]
→ Sin (-A) = -Sin A
→ Sin 18° = (√5-1)/4
→ Sin 54° = (√5+1)/4
→ Sin 90° = 1
→ Cos 60° = 1/2
Answer:
Sonali and Rupali are partners in a firm with capital of 600000 each. They decided to admit Rakhi as a partner with 1/4th share in the profits and losses of the firm. Rakhi bring of 800000 as her share of capital. Their profit and loss account shows a credit balance of 400000 as on the date of admission. Give journal entry to record Goodwill on rakhi's admission
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