Question

Prove that $\sqrt{-1}$=$\frac{1}{\sqrt{-1} }$

Answer 1

Answer:

$\sqrt{-1}$=$\frac{1}{\sqrt{-1} }$

Step-by-step explanation:

[tex] \sqrt{ - 1} = \frac{1}{ \sqrt{ - 1} } (to \: prove) \\ \frac{1}{ \sqrt{ - 1} } \times \frac{ \sqrt{ - 1} }{ \sqrt{ - 1} } = \frac{ \sqrt{ - 1} }{ ({ \sqrt{ - 1} })^{2} }[\tex] = √-1