Math, asked by harshavardhan99, 11 months ago

prove that
 \sqrt{2} is \: irrational

Answers

Answered by deve11
1

Step-by-step explanation:

Let √2 be rational.

√2=p/q where p and q=Z q is not = 0

HCF(p,q)=1

(√2)²=(p/q)²

q²=p²/2

q=p/2

2c=p

q²=(2c)

p/2=c

pand q have at least 2 as common factor.

:√2 is a irrational number.

Answered by Anonymous
0

Step-by-step explanation:

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