Math, asked by premsagar44, 11 months ago

Prove
that
 \sqrt{2 }  +  \sqrt{3}
is An ..
irrational number.​

Answers

Answered by Anonymous
3

Let √2 + √3 = (a/b) is a rational no.

On squaring both sides , we get

2 + 3 + 2√6 = (a2/b2)

So,5 + 2√6 = (a2/b2) a rational no.

So, 2√6 = (a2/b2) – 5

Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.

So, my contradiction is wrong.

So, (√2 + √3) is an irrational no

!!Hope it helps!!

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