Question

Prove that:
$\sqrt{(2p-p^2+1) (2p+p^2+1)} = (p+1)\sqrt{2p-p^2+1}$

Answer 1

Answer:

mark it as brainlest answer please

Step-by-step explanation:

Given (p

2

−2p+1)x

2

−(p

2

−3p+2)x+(p

2

−1)=0

(p−1)

2

x

2

−(p−1)(p−2)x+(p−1)(p+1)=0

(p−1)((p−1)x

2

−(p−2)x+(p+1))=0

Given (p

2

−2p+1)x

2

−(p

2

−3p+2)x+(p

2

−1)=0 has more than two roots

since a quadratic equation has maximum of two roots So it means the above equation should be correct for all values of x

⟹p−1=0⟹p=1