Question

prove that

$\sqrt{3}$
is irrational​

Answer 1

Hey!

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◾ Irrational number ?

➡️ A type of number which can neither be expressed as a terminating decimal or repeating decimal.

$\sqrt{3 \: } is \: an \: irrational \: number$

$\sqrt{3} \: is \: a \: positive \\ integer \: which \: is \: not \\ a \: perfect \: square \: then \: \sqrt{3 } \\ is \: irrational \: number$

Thus , we can say that under root 3 is an Irrational number .

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