Question

Prove that
$\sqrt{3}$
is irrational
Plzz fast​

Answer 1

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Prove that

$\sqrt{3}$

is irrational

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$the \: numbers \: which \: are \: in \: the \: form \: of \: \frac{p}{q} \\ are \: called \: rational \: numbers$

$let \: us \: assume \: that \: \sqrt{3} \: is \: a \: rational \: number$

$\sqrt{3} = \frac{p}{q}$

$\sqrt{3} \: is \: a \: rational \: number$

$because \: \frac{p}{q} \: is \: a \: rational \: number$

$but \: \sqrt{3} \: is \: a \: irrational \: number$

$this \: leads \: us \: contradiction$

$so \: our \: assumption \: \sqrt{3} \: is \: a \: rational \: number\\ \: is \: wrong$

$\sqrt{3} \: is \: a \: irrational \: number$

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Answer 2

Answer:

,

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