Question

Prove That :-

$\sqrt{ \frac{1 - \cos(a) }{1 + \cos(a) } } = \frac{ \sin(a) }{1 + \cos(a) }$
​

Answer 1

Answer:

Question

Prove it

$\frac \pink{sin \: a + cos \: a}{sina \: - cos \: a} = \sqrt{ \frac{1 + sin2a}{1 - sin2a} } </p><p>$

$\bold{\underline \red{Answer-}} </p><p>$

LHS = Prove it

$\frac{sin \: a + cos \: a}{sina \: - cos \: a}$

$\begin{gathered}\begin{gathered}= > \sqrt \green{ \frac{(sin \: a \: + cos \: a) {}^{2} }{(sin \: a \: - cos \: a) {}^{2} } } \\ \\ \\ \\ = > \sqrt \pink{ \frac{ {sin}^{2} a + {cos}^{2} a + 2sin \: a \: cosa}{ {sin}^{2} a + {cos}^{2}a - 2sin \: a \: cosa } } \\ \\ \\ \\ = > \sqrt \blue{ \frac{1 + sin2a}{1 - sin2a} }\end{gathered}\end{gathered} </p><p>$

Hence, Proved

Answer 2

.

I hope it will help you