Question

Prove that : $\sqrt{\frac{1-sinA}{1+sinA }$ = $secA-tanA$

class 10 trigonometry

please thank my answers and no irrelevant questions

Answer 1

Answer:

Step-by-step explanation:

Hey mate here is your answer:

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→$\sqrt{\frac{1-sinA}{1+sinA} } *\sqrt{\frac{1-sinA}{1-sinA} }$ [Multiplying and dividing by √1-sinA],

→$1-sinA/\sqrt{1-sin^2A} =\frac{1-sinA}{cosA}$[∵1-sin²A=cos²A],

→$\frac{1}{cosA}-\frac{sinA}{cosA} =secA-tanA=$R.H.S.

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Hope it helps you good luck to be brainly star.

Answer 2

Answer:

Hello dear actually l don't know