prove that
is an irrational,where p and q are prime
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let assume, √p+√q =a/b
Squaring both sides
(√p+√q)²=(a/b)²
p+q+2√pq=(a/b)²
√pq=1/2{(a/b)²-p-q}
Now p and q are prime positive numbers so that √p and √q are irrational
irrational=rational
So contradiction.
Hope it will help you...
Squaring both sides
(√p+√q)²=(a/b)²
p+q+2√pq=(a/b)²
√pq=1/2{(a/b)²-p-q}
Now p and q are prime positive numbers so that √p and √q are irrational
irrational=rational
So contradiction.
Hope it will help you...
tanyaSharma101:
thanks
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