Question

prove that

$\sqrt x {}^{2} - 36 = 8$
$root \: sign \: is \: also \\ so \: over \: 36$
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Answer 1

Answer:

ans=root x^-36=8

=root x^=8+36

=rootx^=44

=rootx=root 44

=x=44

Answer 2

Answer:

10 & -10

Step-by-step explanation:

√x² - 36 = 8

Squaring both sides.

√x² - 36 = 8²

x² - 36 = 64

x² = 64 + 36

x² = 100

x = √100

x = 10 & - 10