Question

Prove that
$\sqrt{y + \sqrt{2xy - x^{2} } } \: + \sqrt{y - \sqrt{2xy - x^{2} } } \: = \sqrt{2x}$
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Answer 1

Answer:

Prove that

$\sqrt{y + \sqrt{2xy - x^{2} } } \: + \sqrt{y - \sqrt{2xy - x^{2} } } \: = \sqrt{2x}$

Step-by-step explanation:

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