Question

Prove that,
${\sum\limits_{n=m_1}^{m_2} n^3 + \sqrt{n} = \sum\limits_{n={m_1}}^{m_2 }n^3 + \sum\limits_{n=m_1}^{m_2} \sqrt{n}}$


Basically you have to prove that summation can be distributed.
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Answer 1

Answer:

marke as brainlist

the answer is 54