Math, asked by Anonymous, 1 year ago



Prove that :

 { \tan }^{6}  \theta \:  +  \: 3  \: { \tan }^{2} \theta \:  { \sec }^{2} \theta \:  +  \: 1 \:  =  \:  { \sec }^{6} \: \theta

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Answered by kaushik05
6

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