Question

Prove that:
$tan \: 8a = \frac {8tan \: a - 8tan^3 a}{1 - 4tan \: a - 6tan^2 \: a + 4tan^3 \: a + tan^4 \: a}$
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Answer 1

Answer:

$Prove that:</p><p>tan \: 8a = \frac {8tan \: a - 8tan^3 a}{1 - 4tan \: a - 6tan^2 \: a + 4tan^3 \: a + tan^4 \: a}tan8a=1−4tana−6tan2a+4tan3a+tan4a8tana−8tan3a</p><p>$