Prove that
that the tangenth dribiwn at the
chain of a dianelens of a cicle are parallel
Answers
Answered by
0
Step-by-step explanation:
Given : CD and EF are the tangents at the end of the diameter AB of A circle with center O.
To prove : CD||EF
Proof : CD is the tangent of the circle at the point A.
∴CD⊥OA
⇒∠OAD=90
∘
⇒∠BAD=90
∘
.......(i)
EF is the tangent to the circle at the point B.
EF⊥OB
⇒∠OBE=90
∘
⇒∠ABE=90
∘
.......(ii)
from (i) and (ii)
∠BAD=∠ABE=90
∘
These are alternate angles
∴CD∣∣EF
Answered by
2
Answer:
Given : CD and EF are the tangents at the end of the diameter AB of A circle with center O.
To prove : CD||EF
Proof : CD is the tangent of the circle at the point A.
∴CD⊥OA
⇒∠OAD=90
∘
⇒∠BAD=90
∘
.......(i)
EF is the tangent to the circle at the point B.
EF⊥OB
⇒∠OBE=90
∘
⇒∠ABE=90
∘
.......(ii)
from (i) and (ii)
∠BAD=∠ABE=90
∘
These are alternate angles
∴CD∣∣EF
hope it helps
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