prove that the above equation is true
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Answer:
It is true.. Put the values to get the answer.
Answered by
1
Step-by-step explanation:
1/(2sin10)-2sin70
=1/(2sin10)-2sin(90-20)
=1/(2sin10)-2cos20
={1-4cos20.sin10}/sin10
=1/(2sin10){1-2.(2cos20.sin10)}
=1/(2sin10)[1-2{sin(20+10)-sin(20-10)}]
=1/(2sin10)[1-2{sin30-sin10}]
=1/(2sin10)[1-2{1/2-sin10}]
=1/(2sin10)[1-1+2sin10]
=1/(2sin10).[2sin10]
=1
hope it helps ☺
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