prove that the angle between the two tangent drawn from an external point to a circle is supplementry to the angle subtended by the line- segment joining the the point of contact at the centre
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Step-by-step explanation:
<OAP = OBP = 90° ( Since tangent and radius are perpendicular to each other)
In quadrilateral OABP BY angle sum property
<A + <B + <P+ <O= 360°
90 + 90 + < P + <O = 360
<P + < O = 180°
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