Question

Prove that the angle bisector of a triangle divides the side opposite to the angle in the

ratio of the remaining sides.​

Answer 1

Answer:

BBC s, of so if go to do us so to do try i you GM it sh FF we vf to vo

Answer 2

Answer:

hope it HELPS..

please make my answer the branliest

Step-by-step explanation:

Let ΔABC be the triangle. Let AD be the internal bisector of ∠BAC which meet BC at D.

Step2:Since CE||DA and AC is the transversal. Hence, the angle bisector of a triangle divides the side opposite to the angle in the ratio of the remaining sides.