Prove that the angle bisector of a triangle divides the side opposite to the angle in the
ratio of the remaining sides.
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Step-by-step explanation:
Let ΔABC be the triangle. Let AD be the internal bisector of ∠BAC which meet BC at D.
Step2:Since CE||DA and AC is the transversal. Hence, the angle bisector of a triangle divides the side opposite to the angle in the ratio of the remaining sides.
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