Prove that the angle bisectors of interior angles of a rectangle form a square...Please answer this fast
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Answer:
See picture for reference.
Step-by-step explanation:
Let ABCD is a rectangle.
Now, from the figure,
∠1 = 90/2 = 45
and ∠2 = 90/2 = 45
Now, in triangle AXD,
∠AXD = 180 - (45 + 45)
=> ∠AXD = 180 - 90
=> ∠AXD = 90
So, ∠WXY = 90 {vertically opposite angle}
Similarly, in trianlge BCZ
∠CZB = ∠WXY = 90
Since, all the angles are 90, So it will form a square.
P.s; mark as brainliest.
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Arrush:
thanks...but if all the angles are 90 then it'll be a rectangle and not a square
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