PROVE THAT THE ANGLE IN A SEGMENT GREATER THAN A SEMI-CIRCLE IS LESS THAN A RIGHT ANGLE.
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diameter of the circle = AD
∠ACD = 90 ....semi circle is right angled
∠ADC.... is a acute angle
∠ABC = ∠ADC ....angle in a same segment are equal
so,
∠ABC is an acute angle
∠ACD = 90 ....semi circle is right angled
∠ADC.... is a acute angle
∠ABC = ∠ADC ....angle in a same segment are equal
so,
∠ABC is an acute angle
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