Prove that the angle made by two equal chords drawn from a point on the circle
bisected by the diameter through that point.
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Answer:
Given, ∠AEQ=∠DEQ
OL⊥AB,OM⊥DC
In △OLE and △OME
∠OLE=∠OME (Both 90
o
)
∠OEL=∠OEM (given, ∠AEQ=∠DEQ)
OE=OE (common)
∴△OLE≅△OME (AAS congruence)
OL=OM (CPCT)
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ol= om
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