Question

prove that the angle opposite to equal sides of a triangle are equal.
plz solve​

Answer 1

In ΔABD and ΔADC, PROOF

AB=AC(Take it as given)

angleADB=angleADC(AD is bisector)

AD=AD(common)

ΔABD congruent to ΔADC(SAS)

therefore , angleB = angleC(CPCT)

☜☆☞☜☆☞Hence Proved... ☜☆☞