Question

Prove that the angle opposite to longest side of a triangle is always greater than 60 degree​

Answer 1

Answer:

I u are studying the class 9th u will know that there is a theoram that opposite angles are opposite to sides of a triangle mean if one angle is greater then it's opposite side is greater and sane to small angle

hope it helps u

Answer 2

Answer:

hence,proved

Step-by-step explanation:

Consider △ PQR where PR is the longest side

So we get PR > PQ

i.e. ∠ Q > ∠ R ….. (1)

We also know that PR > QR i.e. ∠ Q > ∠ P ….. (2)

By adding both the equations ∠ Q + ∠ Q > ∠ R + ∠ P

So we get 2 ∠ Q > ∠ R + ∠ P

By adding ∠ Q on both LHS and RHS 2 ∠ Q + ∠ Q > ∠ R + ∠ P + ∠ Q We know that ∠ R + ∠ P + ∠ Q = 180o

So we get 3 ∠ Q > 180o By division ∠ Q > 60o

hence,proved

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