Question

prove that the angle subtended by arc of a circle at the center is double the angle subtended by it any point on the remaining part of the circle.​

Answer 1

Step-by-step explanation:

The angle subtended by an arc of a circle at its center is twice the angle it subtends anywhere on the circle's circumference. The proof of this theorem is quite simple, and uses the exterior angle theorem – an exterior angle of a triangle is equal to the sum of the opposite interior angles.