Math, asked by alexapril007, 1 month ago

Prove that the angles opposite to equal sides of a triangle are equal.

Answers

Answered by tusharanshupohekar

0

Answer:

In triangel ABD and ACD

angle A =angleA(AD is bisector of angleA)

AD=AD(common)

angle D=angleD(AD perpendicular BC)

By ASA condtion ABD congruent to ACD

By CPCT angle B=angleC

Hence proved!

Step-by-step explanation:

Pls mark me as brainliest

Previous Question

Next Question

Similar questions

English, 21 days ago

std 8th subject english 1) Make a meaningful sentence of your own from the given word "Mind".

Math, 21 days ago

(i) Simplify: (36 × 106 ×125) ÷ (58 × 6⁴)...

Science, 21 days ago

A metal is released in the electrolysis of a salt. It gets deposited on the - a) anode b) cathode c) half on anode and half on cathode d) sides of the container...

English, 1 month ago

What is meant by Detective??

Math, 1 month ago

I have 12 metres of cloth. I need to cut lengths of 40 centimetres. How many complete lengths can I cut?

Science, 7 months ago

please solve this problem...

English, 7 months ago

The tenth May was significant on the South African soil because it was the ............day by international leaders. (1) Ch 2 class 10 first flight...

English, 7 months ago

How did Abdul kalam earn his first wages?