Question

Prove that the angles opposite to equal sides of a triangle are equal ?

Answer 1

let ABC be a triangle with AD as a median.
the median divide the triangle into two parts
now, in triangles ABD and ADC , we have
AB=AC(given)
AD=DA(since common)
BD=DC(AD is the median)
so by S-S-S rule
triangle ABD is congruent to triangle ADC
=>angle ABD=angle ACD(by CPCT rule)
hope it's the required answer...