prove that the angles opposite to equal sides of an isosceles triangle are equal. Using the above, find
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We are given Isosceles triangle ABC in which AB=AC We need to prove angle B = angle
Let us draw bisector of A and let D be the point of intersection of this bisector of angle A and BC
In triangle BAD and CAD
AB= AC
angle BAD= angle CAD
AD= AD
so BAD congruent to CAD
then angle B = angle C
Hence proved
Let us draw bisector of A and let D be the point of intersection of this bisector of angle A and BC
In triangle BAD and CAD
AB= AC
angle BAD= angle CAD
AD= AD
so BAD congruent to CAD
then angle B = angle C
Hence proved
Answered by
0
Answer:
We are given Isosceles triangle ABC in which AB=AC We need to prove angle B = angle
Let us draw bisector of A and let D be the point of intersection of this bisector of angle A and BC In triangle ABC and CAD AB= AC
angle BAD= angle CAD AD= AD so BAD congruent to CAD
then angle B = angle C
Hence proved
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