Question

Prove that the area of a parallelogram is equal to its base *height​

Answer 1

Answer:

A Parellegram Is A Type Of Quadrateral In Which Both Pair of Sides are Parellal And Equal.

A Parallelogram Has A Property That Says Diagonal Of Parallelogram Divides it Into Two Equal Parts.

Now Suppose There Is A Parallelogram ABCD With Diagonal AB.(Given in The Figure Above)

We Know That Diagonal Bisect The Parallelogram SO :-

$area \: of \: abc \: = area \: of \: adc \\ also \: area \: of \: quadrilateral \: = area \: of \: abc \: + area \: adc \: \\ = )( \frac{1}{2} \times base \times height) + ( \frac{1}{2} \times base \times height) \\ = )since \: both \: are \: are \: equal \\ = ) \frac{base \: \times height}{2} + \frac{base \: \times height}{2} \\ = ) \frac{(base \: \times height) + (base \: \times height}{2} \\ = ) \frac{2(base \: \times height)}{2} \\ = )base \: \times height$

Thus Area Of ABCD(Parallelogram) Is

Base x Height

Hope It Helped

Answer 2

Answer:

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Step-by-step explanation:

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