Question

prove that the area of a rhombus is the half the product of the diagonals

Answer 1

Answer:

AREA OF ABCD = 1/2 x BD x AC

Step-by-step explanation:

let the rhombus be ABCD

the diagonals are BD and AC with intersection at 0

area of ABD = 1/2 x AO x BD  ---(1)

area of DBC = 1/2 x BD x CO   ---(2)

adding 1 and 2 we get

area of ABD + Area of DBC = 1/2 x AO x BD + 1/2 x BD x CO

AREA OF ABCD = 1/2 x BD x(AO + CO)

AREA OF ABCD = 1/2 x BD x AC