Math, asked by digansh8063, 1 year ago

Prove that the area of a trapezium abcd = 1 2 (ab + cd) × cm where, cm is the distance between parallel sides ab and cd

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Answered by ananyadavpkt

13

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Answered by 123Ashishmishra

4

ANS:-AB&CD ARE THE parallel sides,and CM is the height.so,

We know that

Area of trapezium=1/2(b1+b2)×h

=1/2(AB+CD)×CM

ABCD=1/2(AB+CD)×CM

Step-by-step explanation:

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