Question

prove that the area of a trapezium is half the sum of the parallel sides multiplied by the distance between them

Answer 1

Answer:

Step-by-step explanation:

ABCD is a quadrilateral and BD is a diagonal which divides ABCD into two equal triangles.

1.Ar(triangle ABD)=1/2×DB×BA

2.Ar(triangle DBC)=1/2×DB×DC

Therefore,

Area of the quadrilateral drawn =1/2×DV×BA+1/2×DB×DC

1/2DB(BA+DC).

Hence proved......