prove that the area of a triangle is half the product of any of its sides and the corresponding altitude
Answers
Answered by
0
area of triangle=1/2×base×height
Answered by
5
▪♥HELLO MATE♥▪
here is your answer...
⤵⤵⤵
GIVEN : ΔABC, in which AL is altitude to Side BC
TO PROVE : ar(ΔABC) = ½(BC × AL)
CONSTRUCTION : Draw CD || BA and AD || BC through C and A respectively, let they intersect at point D.
PROOF : We have, BA || CD (by construction)
and AD || BC (by contraction)
Therefore, ABCD is a parallelogram.
Since, AC is diagonal of parallelogram ABCD
Therefore, ar(ΔABC) = ½ ar( ||gm ABCD) [ diagonal of parallelogram divide it into two triangles of equal areas ]
= ½ (BC × AL)
[ Area of parallelogram is product of base and corresponding altitudes ]
⤴⤴⤴
Hope it helps you... works for you... and you satisfied with my answer...
.
.
.
.
.
.
.
.
.
.
.
plz plz plz mark me as a brainleist plz plz plz plz plz plz plz...
here is your answer...
⤵⤵⤵
GIVEN : ΔABC, in which AL is altitude to Side BC
TO PROVE : ar(ΔABC) = ½(BC × AL)
CONSTRUCTION : Draw CD || BA and AD || BC through C and A respectively, let they intersect at point D.
PROOF : We have, BA || CD (by construction)
and AD || BC (by contraction)
Therefore, ABCD is a parallelogram.
Since, AC is diagonal of parallelogram ABCD
Therefore, ar(ΔABC) = ½ ar( ||gm ABCD) [ diagonal of parallelogram divide it into two triangles of equal areas ]
= ½ (BC × AL)
[ Area of parallelogram is product of base and corresponding altitudes ]
⤴⤴⤴
Hope it helps you... works for you... and you satisfied with my answer...
.
.
.
.
.
.
.
.
.
.
.
plz plz plz mark me as a brainleist plz plz plz plz plz plz plz...
Similar questions