Question

Prove that the area of
an equilateral triangle
described on one side of
a square is equal to half
the area of the equilateral
triangle described on one
of its diagonals.






(•‿•)​

Answer 1

Answer:

Given:

ABCD is a Square,

DB is a diagonal of square,

△DEB and △CBF are Equilateral Triangles.

To Prove:

A(△DEB)

A(△CBF)

=

2

1

Proof:

Since, △DEB and △CBF are Equilateral Triangles.

∴ Their corresponding sides are in equal ratios.

In a Square ABCD, DB=BC

2

.....(1)

∴

A(△DEB)

A(△CBF)

=

4

3

×(DB)

2

4

3

×(BC)

2

∴

A(△DEB)

A(△CBF)

=

4

3

×(BC

2

)

2

4

3

×(BC)

2

(From 1)

∴

A(△DEB)

A(△CBF)

=

2

1

Step-by-step explanation:

I hope this answers is helpful for you

Answer 2

Answer:

hello

Step-by-step explanation:

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