Prove that the area of an equilateral triangle described on one side of a square is equal to half the area of the equilateral triangle described on one of its diagonals
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area of triangle= 1/2×CD×EF
HERE we know EF perpendicular to CD
so EF = AB=BC=CD=AC
SO area of triangle= 1/2×CD×CD=1/2 ×CD^2
= 1/2× AREA OF SQUARE
HERE we know EF perpendicular to CD
so EF = AB=BC=CD=AC
SO area of triangle= 1/2×CD×CD=1/2 ×CD^2
= 1/2× AREA OF SQUARE
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hope this may help uh..
mark as brainliest...if it really helped uh..
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vidhisaxena29:
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