Prove that the area of isosceles triangle is is equal to root 3 by 4
Answers
Answered by
0
equilateral triangle.
Draw a line from the vertex to the midpoint of the base.
Cut along this line and move half of the triangle to form a rectangle.
If a is the length of a side of the equilateral triangle and h the height then this rectangle has area
1/2 a h
The triangle below, which is half of the rectangle, is a right triangle,
and hence, by Pythagoras' theorem
a2 = h2 + ( a/2)2
Thus h = sqrt( 3/4 a2) = sqrt(3)/2 a. Hence the area of the triangle is
1/2 a h = sqrt(3)/4 a2
Penny
Draw a line from the vertex to the midpoint of the base.
Cut along this line and move half of the triangle to form a rectangle.
If a is the length of a side of the equilateral triangle and h the height then this rectangle has area
1/2 a h
The triangle below, which is half of the rectangle, is a right triangle,
and hence, by Pythagoras' theorem
a2 = h2 + ( a/2)2
Thus h = sqrt( 3/4 a2) = sqrt(3)/2 a. Hence the area of the triangle is
1/2 a h = sqrt(3)/4 a2
Penny
Similar questions