Question

prove that the area of quadrilateral withperpendicular diagonal =1/2×product of digonal​

Answer 1

Step-by-step explanation:

There are three possible case:

There are three possible case:If a > 0 and b > 0 then the resultant product will be positive.

There are three possible case:If a > 0 and b > 0 then the resultant product will be positive.If a < 0 and b > 0 then the result will be zero as a * (a + 1) * … * 0 * … (b – 1) * b = 0.

There are three possible case:If a > 0 and b > 0 then the resultant product will be positive.If a < 0 and b > 0 then the result will be zero as a * (a + 1) * … * 0 * … (b – 1) * b = 0.If a < 0 and b < 0 then the result will depend on the count of numbers (as all the numbers are negative)

There are three possible case:If a > 0 and b > 0 then the resultant product will be positive.If a < 0 and b > 0 then the result will be zero as a * (a + 1) * … * 0 * … (b – 1) * b = 0.If a < 0 and b < 0 then the result will depend on the count of numbers (as all the numbers are negative)If the count of negative numbers is even then the result will be positive.

There are three possible case:If a > 0 and b > 0 then the resultant product will be positive.If a < 0 and b > 0 then the result will be zero as a * (a + 1) * … * 0 * … (b – 1) * b = 0.If a < 0 and b < 0 then the result will depend on the count of numbers (as all the numbers are negative)If the count of negative numbers is even then the result will be positive.Else the result will be negative.

Answer 2

Answer:

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see the above answer