Math, asked by mira71, 1 year ago

Prove that the area of triangle is half of the product of its Base and corresponding height.

Answers

Answered by chanpreet300
14
CP parallel to BA (By Construction)
AP parallel to BC (By Construction)
Therefore BCPA is a parallelogram.
Hence AC is a diagonal of parallelogram BCPA.
Therefore, area of triangle = ½ ar(IIgm BCPA) = ½ × BC × AD (As BC is the base and AD is the altitude of IIgm BCPA).
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Answered by payalchatterje
0

Answer:

follow the explanation part

Step-by-step explanation:

Let base and height of a parallelogram be a and b respectively. We know that the area A of a parallelogram is A = bh.

Now draw a diagonal to form two congruent triangles within the parallelogram. Now shade one of the triangles, which represents the area t of the triangle. We see that this triangle has base b and height h as well. If we shade the other triangle with base b and height h, we get the total area of the parallelogram.

Since there are two triangles with equal area t, we have

area of triangle * 2 = area of parallelogram

2t = bh or t = 1/2*bh

We see that the area of a triangle is one half the base times the height.

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