Prove that the arithmetic sequence 5, 8, 11, ....
contains no perfect squares.
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Step-by-step explanation:
Given Prove that the arithmetic sequence 5, 8, 11, .... contains no perfect squares.
- We need to prove that the arithmetic sequence 5,8,11 has no perfect squares.
- We have a = 5, d = 3
- So we have an = a + (n – 1) d
- = 5 + (n – 1) 3
- = 5 + 3n – 3
- = 3n + 2
- Now we get remainder as 1 or 0 when we divide a perfect square with 3. So we can divide 3m + 2 by 3 we get 2 as a remainder and hence it does not have any perfect square.
Reference link will be
https://brainly.in/question/2312126
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