Question

Prove that the arithmetic sequence with first term 1/2 and common difference 1/3 does not contains any natural number?​

Answer 1

Answer:

no natural number

Step-by-step explanation:

a1= 1/2

d= 1/3

So,

a2=5/6

a3=7/6

a4=9/6

a5=11/6

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Since the denominator of every term will be 6 and numerator will never be a multiple of 6, there can't be any natural number in this sequence as the fraction doesn't get canceled.