prove that the average diffrentation of sin x w.r.t 'x' is cos x
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Step-by-step explanation:
The trigonometric functions \sin(x)sin(x)sine, left parenthesis, x, right parenthesis and \cos(x)cos(x)cosine, left parenthesis, x, right parenthesis play a significant role in calculus. These are their derivatives:
\begin{aligned} \dfrac{d}{dx}[\sin(x)]&=\cos(x) \\\\ \dfrac{d}{dx}[\cos(x)]&=-\sin(x) \end{aligned}
dx
d
[sin(x)]
dx
d
[cos(x)]
=cos(x)
=−sin(x)
The AP Calculus course doesn't require knowing the proofs of these derivatives, but we believe that as long as a proof is accessible, there's always something to learn from it
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