Physics, asked by sanketnandeshwar, 4 months ago

prove that the average kinetic energy per molecule of an ideal gas is 3 /2 kbt

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Answered by jyotishmansarkar10

Answer:

P=13ρC2 where ρ is density of the gas. But PV=RT for one mole of ideal gas. But, 1/2 mC^(2)` is average translational kinetic energy per molecule of a gas. Therefore, average kinetic energy of molecule of an ideal gas is directly proportion to the absolute temperature of the gas.

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