Question

prove that the average kinetic energy per molecule of an ideal gas is 3/2 kbt​

Answer 1

Answer: Prove that the average kinetic energy of a molecule of an ideal gas is directly proportional to the absolute temperature of the gas. P=13ρC2 where ρ is density of the gas. But PV=RT for one mole of ideal gas. But, 1/2 mC^(2)` is average translational kinetic energy per molecule of a gas.

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Answer 2

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