prove that the bisecter of the angles of the linear pair are perpendicular to each other
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If they intersect at right angle and divide them into 2 equal parts
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as we know that be bisector divide angles in half half or same angle or side
so ,
let line is AB
bisector is CD
so angle ACD=angle BCD
angle ACD + angle BCD =180°
angle ACD+ angle ACD=180°
2angle ACD =180°
angle ACD= angle BCD =90°
perpendicular makes the angle of 90°
so bisector of a linear pair are perpendicular to each other
hence prove
hope its help
so ,
let line is AB
bisector is CD
so angle ACD=angle BCD
angle ACD + angle BCD =180°
angle ACD+ angle ACD=180°
2angle ACD =180°
angle ACD= angle BCD =90°
perpendicular makes the angle of 90°
so bisector of a linear pair are perpendicular to each other
hence prove
hope its help
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